Question

9(x-1)^2 + 16(y-3)^2 = 144
Tema elipse

Answer 1

$\frac{(x-1)^2}{1/9} + \frac{(y-3)^2}{1/16} =144 \\ \frac{(x-1)^2}{144/9} + \frac{(y-3)^2}{144/16} =1 \\ \frac{(x-1)^2}{(12/3)^2} + \frac{(y-3)^2}{(12/4)^2} =1\\ \frac{(x-1)^2}{4^2} + \frac{(y-3)^2}{3^2} =1$

Elipse con centro en (1;3) y semiejes mayor y menor a=4 , b=3