Question

(8xy-10x+20y²) ÷4 =
​

Answer 1

$(8xy - 10x + 20 {y}^{2}) \div 4 = \\ \\ \frac{8xy - 10x + 20 {y}^{2} }{4} \\ \\ \frac{2(4xy - 5x + 10 {y}^{2}) }{2} \\ \\ \frac{4xy - 5x + 10 {y}^{2} }{2}$

Espero te sirva ❤