Question

8x - (3x + 2) - [1-7x-(x+1)] -x=0

Answer 1

Respuesta:

x= $\frac{1}{6}$

Explicación paso a paso:

8x - (3x + 2) - [1 -7x-(x+1)] -x = 0

8x - 3x - 2 - [1 -7x-(x+1)] -x = 0

8x - 3x - 2 - [1 -7x - x - 1 ] -x = 0

8x - 3x - 2 - [1 -7x - x - 1 ] -x = 0

8x - 3x - 2 - [ -7x - x ] -x = 0

8x - 3x - 2 - [ -8x ] -x = 0

8x - 3x - 2 + 8x  - x = 0

(Son 12x porque: 5x + 7x = 12x)

12x - 2 = 0

12x = 2

x= $\frac{2}{12}$

x= $\frac{1}{6}$