Question

√81 ÷ 32 x (63 – 152) – 50 + √(10²-4³) ÷ √62

Answer 1

Respuesta:

$\frac{\sqrt{8}\cdot \:1}{32x\left(63-152\right)-50+\sqrt{10^2-\frac{4^3}{\sqrt{62}}}}=\frac{2\sqrt{2}}{-2848x-50+\sqrt{100-\frac{32\sqrt{62}}{31}}}$

Explicación paso a paso:

$\frac{\sqrt{8}\cdot \:1}{32x\left(63-152\right)-50+\sqrt{10^2-\frac{4^3}{\sqrt{62}}}}$

$=\frac{\sqrt{8}}{32\left(63-152\right)x-50+\sqrt{-\frac{4^3}{\sqrt{62}}+10^2}}$

$=\frac{\sqrt{8}}{-2848x-50+\sqrt{-\frac{64}{\sqrt{62}}+100}}$

$=\frac{\sqrt{8}}{-2848x-50+\sqrt{-\frac{64}{\sqrt{62}}+100}}$

$=\frac{2\sqrt{2}}{-2848x-50+\sqrt{-\frac{32\sqrt{2}}{\sqrt{31}}+100}}$

$=\frac{2\sqrt{2}}{-2848x-50+\sqrt{-\frac{32\sqrt{62}}{31}+100}}$

ESPERO QUE TE AYUDE :D

Answer 2

Respuesta:

no me ayudó en nada¯\_(ツ)_/¯