Question

8(x-5)=2x-16

4(5x-2)-2=6(2x+5)

3(3-x)+9=2(x-4)+6

2-4(x+3)=5(x+1)+3

1+1/9x+4/9=-2+x

1/3x+1/10+1/5x=3/10+2/5x

1/4(x-2/5)=2(1/4x+1/5)
me ayudan!!​

Answer 1

Respuesta:

$8(x-5)=2x-16 \\ 8x - 40 = 2x - 16 \\ 8x - 2x = - 16 + 40 \\ 6x = 24 \\ x = \frac{24}{6} \\ x = 4$

$4(5x-2)-2=6(2x+5) \\ 20x - 8 - 2 = 12x + 30 \\ 20x - 10 = 12x + 30 \\ 20x - 12x = 30 + 10 \\ 8x = 40 \\ x = \frac{40}{8} \\ x = 5$

$3(3-x)+9=2(x-4)+6 \\ 9 - 3x + 9 = 2x - 8 + 6 \\ 18 - 3x = 2x - 2 \\ 18 + 2 = 2x + 3 x\\ 20 = 5x \\ \frac{20}{5} = x \\ 4 = x$

$2-4(x+3)=5(x+1)+3 \\ 2 - 4x - 12 = 5x + 5 + 3 \\ - 10 - 4x = 5x + 8 \\ - 10 - 8 = 5x + 4x \\ - 18 = 9x \\ \frac{ - 18}{9} = x \\ - 2 = x$

$1 + \frac{1}{9} x + \frac{4}{9} = - 2 + x \\ 9( 1 + \frac{1}{9}x + \frac{4}{9} ) = 9( - 2 + x) \\ 9 + x + 4 = - 18 + 9x \\ 13 + x = - 18 + 9x \\ 13 + 18 = 9x - x \\ 31 = 8x \\ \frac{31}{8} = x$

$\frac{1}{3} x + \frac{1}{10} + \frac{1}{5} x = \frac{3}{10} + \frac{2}{5} x \\ 30( \frac{1}{3} x + \frac{1}{10} + \frac{1}{5}x ) = 30( \frac{3}{10} + \frac{2}{5}x ) \\ 10x + 3 + 6x = 9 + 12x \\ 16x + 3 = 9 + 12x \\ 16x - 12x = 9 - 3 \\ 4x = 6 \\ x = \frac{6}{4} \\ x = \frac{3}{2}$

$\frac{1}{4} (x - \frac{2}{5} ) = 2( \frac{1}{4} x + \frac{1}{5} ) \\ \frac{1}{4} x - \frac{1}{10} = \frac{1}{2} x + \frac{2}{5} \\ 20( \frac{1}{4} x - \frac{1}{10} ) = 20( \frac{1}{2} x + \frac{2}{5} ) \\ 5x - 2 = 10x + 8 \\ - 2 - 8 = 10x - 5x \\ - 10 = 5x \\ \frac{ - 10}{5} = x \\ - 2 = x$