Question

8× (4× [(3+2÷1)]-10×2)

Answer 1

Respuesta:

8× (4× [(3+2÷1)]-10×2)

$8\times \left(4\times \:\left[\left(3+2\div \:1\right)\right]-10\times \:2\right)\\\\=8\times \:0\\\\=0$

ESTE ES DE OTRA MANERA

8× (4× [(3+2÷1)]-10×2)=8⋅(4⋅[(3+2)]−20)=  

=8⋅(4⋅[(5)]−20)=

=8⋅(20−20)=

=8⋅(0)=

=0