Question

(8-30z)-(5z-3)+(5-2z)=(6z-4)-(4z+2)
me ayudan por favor ​

Answer 1

PROCEDIMIENTO:

$\left(8-30z\right)-\left(5z-3\right)+\left(5-2z\right)=\left(6z-4\right)-\left(4z+2\right)\\\\8-30z-\left(5z-3\right)+5-2z=\left(6z-4\right)-\left(4z+2\right)\\\\-30z-2z-\left(5z-3\right)+8+5=\left(6z-4\right)-\left(4z+2\right)\\\\-32z-\left(5z-3\right)+8+5=6z-4-\left(4z+2\right)\\\\-37z+16=2z-6\\\\-37z=2z-22\\\\-37z-2z=2z-22-2z\\\\-39z=-22\\\\\frac{-39z}{-39}=\frac{-22}{-39}\\\\z=\frac{22}{39}$

Resultado: $z=\frac{22}{39}$

Atte: Sabius95