Question

(7x⁵y⁴)(-4xy)+(34x⁷y⁵)÷(2x)

Answer 1

$7 {x}^{5} {y}^{4} \times ( - 4xy) + 34 {x}^{7} {y}^{5} \div 2x = \\ -28 {x}^{6} {y}^{5} + 17 {x}^{6} {y}^{5} = \\ ( - 28 + 17) {x}^{6} {y}^{5} = \\ - 11 {x}^{6} {y}^{5}$