(×+7)(x-3)=?
x²-14×+49=0
6x²+24x=0
x²+22×+120=0
x²+10×+25=0
x²+5×-126=0
4x²-32x=0
Help meeee con procedimiento doy corona!!!
Respuestas a la pregunta
Explicación:
Primera:
(× + 7)(x - 3) = 0
x + 7 = 0 y x - 3 = 0
x = -7 x = 3
C.S. = {-7,3}
Segunda:
x² - 14× + 49 = 0
(x - 7)² = 0
x - 7 = 0
x = 7
C.S. = {7}
Tercera:
6x² + 24x = 0
6x(x + 4) = 0
6x = 0 y x + 4 = 0
x = 0 x = - 4
C.S. = {-4,0}
Cuarta:
x² + 22× + 120 = 0
x² + 10x + 12x + 120 = 0
x(x + 10) + 12(x + 10) = 0
(x + 10)(x + 12) = 0
x + 10 = 0 y x + 12 = 0
x = -10 x = -12
C.S. = {-12,-10}
Quinta:
x² + 10× + 25 = 0
(x + 5)² = 0
x + 5 = 0
x = -5
C.S. = {-5}
Sexta:
x² + 5× - 126 = 0
x² - 9x + 14x - 126 = 0
x(x - 9) + 14(x - 9) = 0
(x - 9)(x + 14) = 0
x - 9 = 0 y x + 14 = 0
x = 9 x = -14
C.S. = {-14,9}
Séptima:
4x² - 32x = 0
4x(x - 8) = 0
4x = 0 y x - 8 = 0
x = 0 x = 8
C.S. = {0,8}
==============>Felikin<==============