Question

7(x+3)-3(x-2)=16(2x-3)+19

Answer 1

7(x+3)-3(x-2)=16(2x-3)+19

=7x+21-3(x-2)
=7x+21-3x+6
=7x-3x+6+21
=4x+27

16(2x-3)+19
=16*2x+16(-3)
=16*2x-16*3
=32x-48

=32x-48+19
=32x-29

4x+27=32x-29
4x+27-27=32x-29-27
4x=32x-56
4x-32x=32x-56-32x
-28x=-56

$\frac{-28x}{-28}=\frac{-56}{-28}$

x=2