Question

6. Resuelve: 2X+1 . 4x+3 = 16

ayudaaa es para hoy ​

Answer 1

Respuesta:

Explicación paso a paso:

$8x^{2} +10x+3-16=0\\8x^{2} +10x-13=0\\8(x^{2}+\frac{5}{4}x)-13=0\\ 8(x+\frac{5}{8})^{2}-\frac{109}{8} =0\\(2\sqrt{2}x+\sqrt{2} \frac{5}{4})^{2}-(\frac{\sqrt{109} }{2\sqrt{2} })^{2} =0\\(2\sqrt{2}x+\sqrt{2} \frac{5}{4}+\frac{\sqrt{109} }{2\sqrt{2} })(2\sqrt{2}x+\sqrt{2} \frac{5}{4}-\frac{\sqrt{109} }{2\sqrt{2} })=0\\ 8x^{2} +10x-13= \frac{-10+-\sqrt{-316} }{16} = \frac{-10+-2\sqrt{79} i }{16}$