Matemáticas, pregunta formulada por andresherrerasilva, hace 1 año

• 6 – (3 – 10) + (4 – 8 + 2) – (7 + 5 – 1) = • 3 – (5 – 6 + 2) + (4 – 3 + 1) = • (5 – 6 ) + (4 – 1) – (3 – 4 ) + (4) = • (1) x (2) / (2 + 5 +2) = • (2) x (5) + (5 – 3) / (2) =

Respuestas a la pregunta

Contestado por akirajp
1

Respuesta:

• 6 – (3 – 10) + (4 – 8 + 2) – (7 + 5 – 1) = 0

• 3 – (5 – 6 + 2) + (4 – 3 + 1) = 4

• (5 – 6 ) + (4 – 1) – (3 – 4 ) + (4) = 7

• (1) x (2) / (2 + 5 +2) = 2/9

• (2) x (5) + (5 – 3) / (2) = 6

Explicación paso a paso:

• 6 – (3 – 10) + (4 – 8 + 2) – (7 + 5 – 1) =

1. Calcular

= 6-(-7)+(-2)-11

2. Remover paréntesis y calcular

= 6+7-2-11

= 0

• 3 – (5 – 6 + 2) + (4 – 3 + 1) =

1. Calcular

= 3-1+2

= 4

• (5 – 6 ) + (4 – 1) – (3 – 4 ) + (4) =

1. Calcular y restar

= (-1)+3-(-1)+4

2. Eliminar opuestos y calcular la suma

= 7

• (1) x (2) / (2 + 5 +2) =

1. Multiplicar y calcular la suma

= 2/2+5+2

= 2/9

• (2) x (5) + (5 – 3) / (2) =

1. Multiplicar y restar

= 10+2 / 2

2. Sumar los números

= 12/2

3. Simplificar

=6

Espero que te sirva !

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