Question

(6+12)³÷4+2(4+3)÷4²=​

Answer 1

Respuesta:

Respuesta

4,4/5

454

a] 7*3 + (6 + 2*(2³/4 + 3*2) - 7*√1) + 9/3 =

21 + (6 + 2*(8/4 + 6) - 7*1) +3 =

21 + (6 + 2*(2 + 6) - 7) + 3 =

21 + (6 + 2*8 - 7) + 3 =

21 + (6 + 16 - 7) + 3 =

21 + 15 + 3 = 39

Solución: 39

b]14*(7 + 4*3*((-2)²*2 - 6))) + (2² + 6 - 5*3) + 3 - (5 - 2³/2) =

14*(7 + 12*(4*2 - 6))) + (4 + 6 - 5*3) + 3 - (5 - 8/2) =

14*(7 + 12*(8 - 6))) + (4 + 6 - 15) + 3 - (5 - 4) =

14*(7 + 12*2)) + (-5) + 3 - (1) =

14*(7 + 24)) - 5 + 2 =

14*(31) - 5 + 2 =

434 - 3 = 431

Solución: 431

c]5*(5 + 3*2/6 - 4)*(4/2 - 3 + 6)/(7 - 8/2 - 2)² =

5*(5 + 1 - 4)*(2 - 3 + 6)/(7 - 4 - 2)² =

5*(2)*(5)/(1)² =

50/1 = 50

Solución: 50

d]((17-15)³ + (7 - 12)²)/((6 - 7)*(12 - 23)) =

((2)³ + (-5)²)/((-1)*(-11)) =

(8 + 25)/(11) =

33/11 = 3

Solución: 3