Matemáticas, pregunta formulada por javier9918, hace 9 meses

5xab3 + 10xb2-5xab – 10x

Respuestas a la pregunta

Contestado por edu0702839
0

Respuesta:

−ba2−2ba+b2−b+x2+2bx−{05xa⋅(b)3+10b2x−5bax−10x}=0

x2−5b3ax−10b2x+5bax+2bx+10x+b2−ba2−2ba−b=0

(1)⋅x2+(−5b3a−10b2+5ba+2b+10)⋅x+(b2−ba2−2ba−b)=0

x=−(−5b3a−10b2+5ba+2b+10)±(−5b3a−10b2+5ba+2b+10)2−4⋅(b2−ba2−2ba−b)−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−√2

x=5b3a+10b2−5ba−2b−10±25b6a2+100b5a−50b4a2−20b4a+100b4−200b3a−40b3+25b2a2+20b2a−196b2+100ba+40b+100−(4b2−4ba2−8ba−4b)−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−√2

x=5b3a+10b2−5ba−2b−10±25b6a2+100b5a−50b4a2−20b4a+100b4−200b3a−40b3+25b2a2+20b2a−200b2+4ba2+108ba+44b+100−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−√2

−ba2−2ba+b2−b+x2+2bx−{05xa⋅(b)3+10b2x−5bax−10x}=0

x2−5b3ax−10b2x+5bax+2bx+10x+b2−ba2−2ba−b=0

Contestado por liacatzin2008
0

Respuesta:

no se losiento

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