Question

(5x-4y : 19) (7x+3y : 18) AYUDAAAAAAMEEE PORFAVOR AHORAAAA​

Answer 1

Respuesta:

$\boxed{\mathrm{\left(\frac{5x-4y}{19}\right)\left(\frac{7x+3y}{18}\right)}}$

$\mathrm{Resolvemos:}$

$\mathrm{\left(\frac{5x-4y}{19}\right)\left(\frac{7x+3y}{18}\right)=\frac{5x-4y}{19}\cdot \frac{7x+3y}{18}}$

$\mathrm{Recordar \ que:}$

$\bold{\frac{a}{b}\cdot \frac{c}{d}=\frac{a\:\cdot \:c}{b\:\cdot \:d}}$

$\mathrm{\frac{\left(5x-4y\right)\left(7x+3y\right)}{19\cdot \:18}}$

$19\cdot \:18=342$

Solución:

$\boxed{\mathrm{\frac{\left(5x-4y\right)\left(7x+3y\right)}{342}}}$

Saludos...