Question

(5x)/(2) + (3x + 1)/(2) = 1
hallar x

Answer 1

$\frac{5x}{2} + \frac{3x+1}{2} =1$

$\frac{5x+3x+1}{2} =1$

$5x+3x+1 = 2(1)$

$8x + 1 = 2$

$8x = 2 - 1$

$8x = 1$

$x= \frac{1}{8}$

Comprobación:

$\frac{5(\frac{1}{8}) }{2} + \frac{3(\frac{1}{8}) +1}{2}= 1$

$\frac{\frac{5}{8} }{\frac{2}{1} } + \frac{\frac{3}{8}+\frac{1}{1} }{2} =1$

$\frac{5(1)}{8(2)} + \frac{\frac{3(1)+8(1)}{8(1)} }{2} = 1$

$\frac{5}{16} + \frac{\frac{3+8}{8} }{2}=1$

$\frac{5}{16} + \frac{\frac{11}{8} }{\frac{2}{1} } = 1$

$\frac{5}{16} + \frac{11(1)}{8(2)} = 1$

$\frac{5}{16} + \frac{11}{16} = 1$

$\frac{16}{16} = 1$

$1 = 1$    

Respuesta:

x = 1/8