Question

5log2 16-log3 9+log5 (1/25)

Answer 1

Respuesta:

$5log_216-log_39+log_5\left(\frac{1}{25}\right)=16$

Explicación paso a paso:

$5log_216-log_39+log_5\left(\frac{1}{25}\right)=log_2({2^{4}})^{5} -log_3(3^{2})+log_5\left(5^{-2}\right)\\5log_216-log_39+log_5\left(\frac{1}{25}\right)=log_2({2^{20}) -log_3(3^{2})+log_5\left(5^{-2}\right)=20-2-2=16$