Question

5²x5¹+3⁴÷3²- [(2²)⁵]⁰ = ?

2x(7-3)+4² - 9x0 - 3² ÷ 3² = ?

(26-13) ÷ 13 + 6⁷ ÷ 6³ ÷ 6⁴ - 2² = ?

Ayudaaaa :(​

Answer 1

Explicación paso a paso:

5²x5¹+3⁴÷3²- [(2²)⁵]⁰ = $\frac{125x + 81}{8}$

2x(7-3)+4² - 9x0 - 3² ÷ 3² = $\frac{8x + 7}{9}$

(26-13) ÷ 13 + 6⁷ ÷ 6³ ÷ 6⁴ - 2² = -2

Answer 2

Explicación paso a paso:

• ${5}^{3} + {3}^{2} - {2}^{0} \\ 125 + 9 + 1 = 135$
• $2 \times 4 + 16 - 0 - {3}^{0} \\ 8 + 16 - 1 =23$
• $13 \div 13 + {6}^{0} - 4 \\ 1 + 1 - 4 = - 2$