Question

5. Suprimir paréntesis, corchetes y llaves y luego resolver la suma algebraica. a) 107-{ 32+ [15-9+ (24 - 10) - (35-20)]} -[ 6+ (19-5)] =. b) 3+ (16+15-[9+(12-5)-(2+3)] +8} - (42-15) + (2 + 4) = c) {31+ [27- (16+41-50 )] + (19+7-16)} + [247- (97+31)]= d) {26+ [54 - (9+7)]-[32- (26 - 11)] + 3} - (19+6)= e) (12-6-3)-{-[-8+ (5-2) + 3]}=1 f) {16+ [9- (15-10) ]} - {18 - [12 - (6+3)]}= g) 1-{5+[-15- (9 + 3) + 1]}= ​

Answer 1

Respuesta:

Explicación paso a paso:

a) 107-{ 32+ [15-9+ (24 - 10) - (35-20)]} -[ 6+ (19-5)] = 50

b) 3+ (16+15-[9+(12-5)-(2+3)] +8} - (42-15) + (2 + 4) = 10

c) {31+ [27- (16+41-50 )] + (19+7-16)} + [247- (97+31)] = 180

d) {26+ [54 - (9+7)]-[32- (26 - 11)] + 3} - (19+6) = 23

e) (12-6-3)-{-[-8+ (5-2) + 3]} = 1

f) {16+ [9- (15-10) ]} - {18 - [12 - (6+3)]} = 5

g) 1-{5+[-15- (9 + 3) + 1]} = ​22