Question

5 moles de nitrato cuprico

Answer 1

Cu(NO3)2

Cu = 63,5

N = 14

O = 16

MrCu(NO3)2=[63,5(1)+14(2)+6(16)]g/mol

MrCu(NO3)2= 187,5g/mol

187,5g/mol × 5mol = 937,5gCu(NO3)2