Question

5. log3 (x+3) + log3 (×-3)=3 ayuda es urgente ​

Answer 1

Respuesta:

Explicación paso a paso:

Answer 2

Respuesta:

Explicación paso a paso:

$\log _{10}\left(3\right)\left(x+3\right)+\log _{10}\left(3\right)\left(-3\right)=3$

$\log _{10}\left(3\right)\left(x+3\right)-3\log _{10}\left(3\right)=3$

$\log _{10}\left(3\right)\left(x+3\right)-3\log _{10}\left(3\right)+3\log _{10}\left(3\right)=3+3\log _{10}\left(3\right)$

$\log _{10}\left(3\right)\left(x+3\right)=3+3\log _{10}\left(3\right)$

$\frac{\log _{10}\left(3\right)\left(x+3\right)}{\log _{10}\left(3\right)}=\frac{3}{\log _{10}\left(3\right)}+\frac{3\log _{10}\left(3\right)}{\log _{10}\left(3\right)}$

$x+3=\frac{3+3\log _{10}\left(3\right)}{\log _{10}\left(3\right)}$

$x+3-3=\frac{3+3\log _{10}\left(3\right)}{\log _{10}\left(3\right)}-3$

$x=\frac{3+3\log _{10}\left(3\right)}{\log _{10}\left(3\right)}-3$