Question

5. Halla P
P= sen 1920° [sen (-60) - cos(-45)]​

Answer 1

Respuesta:

✅

P= sen 1920° [sen (-60°) - cos(-45°)]​

sen 1920° = sen [ 360°(5) + 120° ]

sen 1920° = sen 120°

...

sen 120° = sen (180° - 60°)

sen 120° = sen 60°

...

Entonces...

P= sen 1920° [sen (-60°) - cos(-45)]​

P = sen 60° [ - sen 60° + cos 45° ]

P = $\frac{\sqrt{3} }{2}[-\frac{\sqrt{3} }{2} + \frac{\sqrt{2} }{2}]$

P = $\frac{\sqrt{3} }{2} [\frac{-\sqrt{3} + \sqrt{2} }{2} ]$

P = $\frac{-\sqrt{3}.\sqrt{3}+\sqrt{3} .\sqrt{2} }{2.2}$

P = $\frac{-3+\sqrt{6} }{4}$

Answer 2

Respuesta:

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