Question

5(3x+2)+3(6x+8)=67
7(2x+1)+6(3x+4)=31

Answer 1

5(3x+2)+3(6x+8)=67
15x+10+18x+24=67
15x+18x=67-10 -24
33x = 33
x=33/33
x=1

7(2x+1)+6(3x+4)=31
14x+7+18x+24=31
14x+18x=31-7-24
32x= 0
x=0/32
x=0

Answer 2

$5(3x+2)+3(6x+8)=67 \\ \\ (5.3x+5.2)+(3.6x+3.8)=67 \\ \\ (15x+10)+(18x+24)=67 \\ \\ 15x+10+18x+24=67 \\ \\ 33x+34=67 \\ \\ 33x=33 \\ \\ \frac{33x}{33} = \frac{33}{33} \\ \\ x=1 \\ ------------------------- \\ \\ 7(2x+1)+6(3x+4)=31 \\ \\ 14x + 7 + 18 x + 24 = 31 \\ \\ 14x + 7 + 18x + 24 = 31 \\ \\ 32 x + 31 = 31 \\ \\ 32x32=0 \\ \\ x=0 \\ \\ \\ Saludos,Cordiales...!$