Question

-5(3m-4)-6(2-(4m-(-5)))=11​

Answer 1

RESOLVER:

$-5\left(3m-4\right)-6\left(2-\left(4m-\left(-5\right)\right)\right)=11$

$-5\left(3m-4\right)-6\left(2-\left(4m+5\right)\right)=11$

Desarrollamos:

$-5\left(3m-4\right)-6\left(2-\left(4m+5\right)\right)$

Expandimos

$2-\left(4m+5\right):-4m-3$

$-5\left(3m-4\right):-15m+20$

$-6\left(-4m-3\right):24m+18$

$=-15m+20+24m+18$

Ahora simplificamos

$-15m+20+24m+18=9m+38$

$=9m+38$

$9m+38=11$

Restamos el 38 de ambos lados

$9m+38-38=11-38$

Simplificamos

$9m=-27$

$\frac{9m}{9}=\frac{-27}{9}$

$\boxed{=m=-3}$

$Buena\:suerte\:con\:tus\:tareas\::ProfeAndresFelipe :)$