5[2x-4(3x-1)]=10x+20
Respuestas a la pregunta
Contestado por
3
- 5(2x−4(3x+1))=−10x+20
- 5(2x−4(3x+1))=−10x+20 5(2x-12x-4)=-10x+20
- 5(2x−4(3x+1))=−10x+20 5(2x-12x-4)=-10x+205(-10x-4)= -10x+20
- 5(2x−4(3x+1))=−10x+20 5(2x-12x-4)=-10x+205(-10x-4)= -10x+20-50x-20= -10x+20
- 5(2x−4(3x+1))=−10x+20 5(2x-12x-4)=-10x+205(-10x-4)= -10x+20-50x-20= -10x+20-50x+10x=20+20
- 5(2x−4(3x+1))=−10x+20 5(2x-12x-4)=-10x+205(-10x-4)= -10x+20-50x-20= -10x+20-50x+10x=20+20−40x=40
- x= -1
Explicación paso a paso:
v:
Otras preguntas