Question

(–5)² – 7x⁰ + (–3)³; x ≠ 0
con resolucion
(3/5)⁻¹ + (3/7)⁻¹
con resolucion
16ᵃ ⁺ ¹ ⋅ 2¹⁻ ⁴ ᵃ=
con resolucion

Answer 1

Respuesta:

(-5)²- 7x0²+(-3);x=0

25-7x0+1

25-0+1

26

(3/5)⁻¹ + (3/7)⁻¹

5         7

-    +    -

3         3

4

16ᵃ ⁺ ¹ ⋅ 2¹⁻ ⁴ ᵃ=

(este no pude)

Explicación paso a paso: