Question

(4x²–6x+9)+(–x²+7x–9)​

Answer 1

$(4x²–6x+9)+(–x²+7x–9)$

$4x² \: – \: 6x+9 \: –x²+7x \: – \: 9$

$(4 {x}^{2} - {x}^{2} ) + ( - 6x + 7x) + ( 9 - 9)$

$3 {x}^{2} + x + 0$

$3 {x}^{2} + x$