Question

4X² + 20x + 1 = 0


Ayuda B)

Answer 1

Tema:ecuacion cuadratica

$4 {x}^{2} + 20x + 1 = 0 \\ a {x}^{2} + bx + c = 0 \\ \\ \\ a = 4 \\ \\ b = 20 \\ \\ c = 1$

Formula general

$x = \frac{ - b \: \pm \sqrt{( {b)}^{2} - 4ac } }{2a}$

$x = \frac{ - (20) \pm \sqrt{ {(20)}^{2} - 4(4)(1) } }{2(4)}$

$x = \frac{ - 20 \: \pm \sqrt{400 - 16} }{8}$

$x = \frac{ - 20 \: \pm \: \sqrt{384} }{8}$

$x = \frac{ - 20 \pm \: 19.5959}{8}$

$x1 = \frac{ - 20 + 19.5959}{8} = \frac{ - 04041}{8} \\ = - 0505$

$x2 = \frac{ - 20 - 19.5959}{8} = \frac{ - 39.5959}{8} = - 4.9494 \\ = 4.9495$

$rpta = \\ \\ \\ x1 = - 0505 \\ \\ x2 = 4.9495$