Question

4X²+12x-40=0 formula general con procedimiento :)

Answer 1

4X² + 12X - 40 = 0 (Podemos simplificar por 4)

X² + 3X - 10 = 0

Por factorizacion:

X² + 3X - 10 = 0

3X = 5X - 2X

X² + 5X - 2X - 10 = X² - 2X + 5X - 10

(X² - 2X) + (5X - 10) =  X(X - 2) + 5(X - 2)

X(X - 2) + 5(X - 2) = (X + 5)(X - 2)

X² + 3X - 10 = (X + 5)(X - 2)

Por formula general.

4X² + 12X - 40 = 0

Donde: a = 4; b = 12; c = -40

$X=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$X=\frac{-(12)\pm \sqrt{(12)^2-4(4)(-40)}}{2(4)}$

$X=\frac{-12\pm \sqrt{144 +640}}{8}$

$X=\frac{-12\pm \sqrt{784}}{8}$

$X=\frac{-12\pm \ 28}{8}$

X1 = [-12 + 28]/8 = 16/8 = 2

X1 = 2

X2 = [-12 - 28]/8 = -40/8 = -5

X2 = -5

Soluciones: X = 2 y X = -5

4X² + 12X - 40 = (X - 2)(X + 5)