Question

(4x+6y³ )³ porfa ayuda qwq​

Answer 1

¡Hola!

$\bold{PONTENCIACI \acute{O}N.}$

$(4x + 6 {y}^{3} {)}^{3} \\ \\ \\ (4x {)}^{3} + \purple{3}(4x {)}^{2} (6 {y}^{3} ) + \purple{3}(4x)(6 {y}^{3} {)}^{2} + (6 {y}^{3}{)}^{3} \\ \\ \\ \\ 64 {x}^{1 \cdot3} + 3(16 {x}^{1 \cdot2} )(6 {y}^{3} ) + 3(4x)(36 {y}^{2 \cdot3} ) + 216 {y}^{3 \cdot3} \\ \\ \\ \boxed{ \boxed{ \pink{64 {x}^{3} + 288 {x}^{2} {y}^{3} + 432x {y}^{6} + 216 {y}^{9} }}}$

Espero que sirva y saludos.

Answer 2

Respuesta:

$\left(4x+6y^3\right)^3$

Formula Binomio al Cubo

$\left(a+b\right)^3=a^3+3a^2b+3ab^2+b^3$

$\left(4x\right)^3+3\left(4x\right)^2\cdot \:6y^3+3\cdot \:4x\left(6y^3\right)^2+\left(6y^3\right)^3$

$\boxed{64x^3+288x^2y^3+432xy^6+216y^9}$

Saludos...