Question

4x-(2x+3)(3x-5)=49-(6x_1)(x-2)​

Answer 1

Respuesta:

4x -(2x+3)(3x-5) = 49 -(6x-1)(x-2)

4x-(6 x^{2} -10x + 9x -15) = 49 - (6 x^{2} -12x - 1x +2)4x−(6x2−10x+9x−15)=49−(6x2−12x−1x+2)

4x - 6x^{2} + 10x - 9x+15 = 49 - 6 x^{2} +12x+x-24x−6x2+10x−9x+15=49−6x2+12x+x−2

4x + x +15 = 49 +13x - 2

5x +15 = 47 +13x

15 - 47 = 13x-5x

-15 = 2x

-15/2 = x