Question

(4x^2-14x +6) / (2x-1) + x^2-2=0

Answer 1

Respuesta:

Explicación paso a paso:

(4x^2-14x +6) / (2x-1) + x^2-2=0

2x3+3x2−18x+8 /2x−1 =0

2x3+3x2−18x+8=0

(2x−1)(x−2)(x+4)=0

2x−1=0  x−2=0 x+4=0

x= 1 /2

x=2 x=−4

x= 1 /2

x=2

x=−4

x=2  x=−4