Question

4m(a²+x-1)+3n(x-1+a²)

(a+3)(a+1) -4(a+1)

(x+y) (n+1) -3(n+1)

a(n+2) +n+2

factor común polinomio (por agrupación)
ayudenme

Answer 1

4m(a²+x-1)+3n(x-1+a²) =
(a²+x-1) (4m+3n)

(a+3)(a+1) -4(a+1) =
(4a—12)(a+1)

(x+y) (n+1) -3(n+1)=
(n+1)(—3x—3y)

a(n+2) +n+2=
(n+2)(a+1)