Question

(4ac - 7ac) + (5ac - 6ac) 2ac
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Answer 1

Respuesta:

(4ac - 7ac) + (5ac - 6ac) 2ac

4ac - 7ac + (5ac - 6ac) 2ac

4ac - 7ac + 2 ac * (5ac - 6ac)

4ac - 7ac + 2 ac * (5ac - 6ac)

- 3ac + 2 ac * (5ac - 6ac)

- 3ac + 2 ac * (5ac - 6ac)

- ac (3 - (2 * ( 5ac - 6ac ))

- ac (3 - (2 * ( 5ac - 6ac ))

- ac (3 - 2 * ( - ac ))

- ac (3 - 2 * ( - ac ))

- ac ( 3 + 2 ac )

- 3ac -$2a^{2}$ - $c^{2}$

Explicación paso a paso: