Question

(-4a a la dos+b ala 3) a la dos

Answer 1

$(-4a^{2} + b{^{3} } )^{2} =16a^{4} -8 a^{2} b^{3} +b^{6}$

Answer 2

Resolver.

Aplicas.
Productos Notables.
(a - b)² = a² - 2ab + b²

(-4a² + b³)² =
(b² - 4a²)² =
(b³)² -  2(b³)(4a²) + (4a²)² =
b⁶ - 8b³a² + 4²a⁴ =
b⁶ - 8b³a² + 16a⁴

Respuesta.
b⁶ - 8b³a² + 16a⁴