Question

-4a-12b+c÷3a+9c-b÷-5c+3b+2a

Answer 1

$= - 4a + - 12b + \frac{1}{3} ac + 6c + \frac{1}{5} bc + 3b + 2a$

Combinar términos comunes:

$=−4a+−12b+ \frac{1}{3} ac+9c+ \frac{1}{5} bc+3b+2a$

$= ( \frac{1}{3} ac) + ( \frac{1}{5} bc) + ( - 4a + 2a) + ( - 12b + 3b) + (9c)$

$solución:</p><p></p><p>= \frac{1}{3} ac+ \frac{1}{5} bc−2a−9b+9c</p><p></p><p>$