Question

√45+?√5-√20=6√5
∛8 ala 4 + ∛? ala 4 - ∛64 ala 4 = x∛x

Answer 1

$\sqrt{45} +x \sqrt{5}- \sqrt{20} = 6\sqrt{5}$

$3 \sqrt{5} +x \sqrt{5} -2 \sqrt{5} = 6 \sqrt{5}$

$\sqrt{5} + x\sqrt{5} = 6 \sqrt{5}$

$x \sqrt{5} = 6\sqrt{5} -\sqrt{5}$

$x \sqrt{5} = 5 \sqrt{5}$

x = 5


$\sqrt[3]{8 x^{4} }+ \sqrt[3]{a x^{4} } - \sqrt[3]{64x} = x \sqrt[3]{x}$

$2x \sqrt[3]{x} + x\sqrt[3]{27x} - 4x\sqrt[3]{x} = x \sqrt[3]{x}$

$2x \sqrt[3]{x} +3x \sqrt[3]{x} -4x \sqrt[3]{x} = x\sqrt[3]{x}$

$x \sqrt[3]{x} =x \sqrt[3]{x}$

el valor de a =  27

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