Question

42+2
$( \sqrt[3]{0.064 } + \sqrt{0.81) {}^{2} }$
​

Answer 1

Respuesta:

42+2 = 44

$( \sqrt[3]{0.064 } + \sqrt{0.81} )^{2} \\\\( \sqrt[3]{0.064 })^{2} + (\sqrt{0.81} )^{2} \\\\\sqrt[3]{0.064^{2} }+ 0.81\\\\\sqrt[3]{0.004096}+ 0.81\\\\\sqrt[3]{0.16^{3} }+ 0.81\\\\0.16+0.81\\\\0.97$