Question

40°- resolver aplicando propiedades.
a) 10².10-⁵.10⁷

b)10.10⁹ : 10³

c) 10⁶.10-2 : 10-⁵

d)
(10¹¹ )
______
(10⁴.10²)

e)(10³.10⁷)
_____
(10.10²)

f) (10-⁶.10²)
_____
(10-³.10-⁵)

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Answer 1

Respuesta:

Saludos

Explicación paso a paso:

${10}^{2} \times {10}^{ - 5} \times {10}^{7} = {10}^{2 - 5 + 7} = {10}^{4}$

$10 \times {10}^{9} \div {10}^{3} = {10}^{1 + 9} \div {10}^{3} = {10}^{10 - 3} = {10}^{7}$

${10}^{6} \times {10}^{ - 2} \div {10}^{ - 5} = {10}^{6 -2} \div {10}^{ - 5} = {10}^{4 - ( - 5)} = {10}^{9}$

$\frac{ {10}^{11} }{ {10}^{4} \times {10}^{2} } = \frac{ {10}^{11} }{ {10}^{6} } = {10}^{11 - 6} = {10}^{5}$

$\frac{ {10}^{3} \times {10}^{7} }{10 \times {10}^{2} } = \frac{ {10}^{10} }{ {10}^{3} } = {10}^{10 - 3} = {10}^{7}$

$\frac{ {10}^{ - 6} \times {10}^{ 2} }{ {10}^{ - 3} \times {10}^{ - 5} } = \frac{ {10}^{ - 6 + ( 2)} }{ {10}^{ - 3 + - (5)} } = \frac{ {10}^{ - 4} }{ {10}^{ - 8} } = {10}^{ - 4 - ( - 8)} = {10}^{ 4}$

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