Question

4(x_3)_5(x+2)=7(3x_1)+29​

Answer 1

Respuesta:

4(x-3)-5(x+2) = 7(3x-1)+29

4(x)-4(3)-5(x)-5(2) = 7(3x)-7(1)+29

4x-12-5x-10 = 21x-7+29

(4-5)x-(12+10) = 21x+22

-x-22 = 21x+22

-22-22 = 21x+x

-44 = 22x

-44/-22 = 22x/-22

2 = -x

-2 = x

x = -2

Verificación :

4((-2)-3)-5((-2)+2) = 7(3(-2)-1)+29

4(-5)-5(0) = 7(-6-1)+29

-20-0 = 7(-7)+29

- 20 = - 49+29

- 20 = - 20

R// El valor de " x " es - 2 .