Question

4. Si: AC = 3AB. Hallar "x"​

Answer 1

Respuesta

AC=3AB  

C-A=3(B-A)  

C - (-1,2) = 3[(2,-5)-(-1,2)]

C - (-1,2) = 3[(2+1,-5-2) ]  

C - (-1,2) = 3(3,-7)

C- (-1,2) = (9,-21)  

C = (9,-21)+(-1,2)

C = (9+(-1); -21+2)

C = (8,-19)

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