Question

4. Resolver: \sqrt{9x-8}-\sqrt{4x+1\ }=\ \sqrt{x-3}

Answer 1

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$\bf\green{Resolvemos:}$

$\sqrt{9x - 8} - \sqrt{4x + 1} = \sqrt{x - 3}$

$\sqrt{9 \times 12 - 8} - \sqrt{4 \times 12 + 1} = \sqrt{12 - 3}$

$3 = 3$

$x = 12$

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$\boxed{x=12}$

$\bf\blue{ATT: ★Alex★}$