Question

4 Cos³∝ -Cos∝)/ 3Sen∝ - 4Sen³∝

Answer 1

${ \frac{4cos^3x-cosx}{3senx-4sen^3x} =}\\\\{ \frac{cosx(4cos^2x-1)}{senx(3-4sen^2x)} =}\\\\{ \frac{cosx(4(1-sen^2x)-1)}{senx(3-4sen^2x)} =}\\\\{ \frac{cosx(4-4sen^2x-1)}{senx(3-4sen^2x)} =}\\\\{ \frac{cosx(3-4sen^2x)}{senx(3-4sen^2x)} =}\\\\{ \frac{cosx}{senx} =}\\\\{\boxed{ctgx}}\\\\{\mathbf{salu2.!!\ :)}}\\{\mathbf{Wellington}}$