Question

4.- Calcular la molalidad de una disolución de 0,978 moles de glicerina (C3H8O3) en 0,2 kg de agua (disolvente)​

Answer 1

Respuesta:

* Molecular weight of C3H803 = 3.12 + 8. 1+ 3.16 = 92 g / mol (see Periodic Table)

* Moles in 90 grams of C3H803 = C3H803 mass / molecular weight = 90/92 = 0.98 moles

* Molality moles C3H803 / kg of = solvent = 0.98 / 0.2 = 4.9 m