Question

4) 40 x²-x-6=0 quien me puede ayudar xfa ​

Answer 1

40x^2 - x - 6 = 0

a= 40; b= -1; c= - 6

∆ = b^2 - 4(a)(c)

∆ = (- 1)^2 - 4(40)(-6)

∆ = 1 + 960

∆ = 961 = 31^2

x = - b ±√∆ / 2(a)

x = - (-1) ±√31^2 /2(40)

x = 1 ± 31/80

x1 = 1 + 31/80

x1 = 32/80

x1 = 2/5

x2 = 1 - 31/80

x2 = - 30/80

x2 = - 3/8

CS = { - 3/8, 2/5}