Question

4-3[x-(5x-4)]-x²=3-(x+1) ²

Answer 1

Respuesta:

$\texttt{x=} \frac{ \texttt{5}}{ \texttt{7}}$

Explicación paso a paso:

$\texttt{4-3[x-(5x-4)]-x}^{ \texttt{2}} \texttt{ = 3-(x+1)}^{ \texttt{2}}$

$\texttt{4-3[x-5x+4]-x}^{ \texttt{2}} \texttt{ = 3-(x}^{ \texttt{2}} \texttt {+2x+1)}$

$\texttt{4-3[-4x+4]-x}^{ \texttt{2}} \texttt{ = 3-x}^{ \texttt{2}} \texttt {-2x-1}$

$\texttt{4+12x-12-x}^{ \texttt{2}} \texttt{ = -x}^{ \texttt{2}} \texttt {-2x + 2}$

$\texttt{4+12x-12 = -2x+2}$

$\texttt{12x+2x = 2+12-4}$

$\texttt{14x = 10}$

$\texttt{x=} \frac{ \texttt{10}}{ \texttt{14}}$

$\texttt{x=} \frac{ \texttt{5}}{ \texttt{7}}$