Question

( - 4/3 x 2 y ) ( 5/4 x 3 y 2 – 2/6 x 2 y 3 – 7/3 x y – 2/4 )= PORFA AYUDEN

Answer 1

Explicación paso a paso:

( - 4/3x²y ) ( 5/4 x³y² – 2/6x²y³ – 7/3 xy – 2/4 )=

$( - \frac{ 4}{3} {x}^{2} y)( \frac{5}{4} {x}^{3} {y}^{2} - \frac{2}{6} {x}^{2} {y}^{3} - \frac{2}{4} ) = \\ - \frac{20}{12} x ^{5} y ^{3} - \frac{8}{18} {x}^{4} {y}^{4} + \frac{8}{12} {x}^{2} y = \\ \ - \frac{20 \div 4}{12 \div 4} x ^{5} y ^{3} - \frac{8 \div 2}{18 \div 2} {x}^{4} {y}^{4} + \frac{8 \div 4}{12 \div 4} {x}^{2} y = \\ \ - \frac{5}{3} x ^{5} y ^{3} - \frac{4}{9} {x}^{4} {y}^{4} + \frac{2}{3} {x}^{2} y =$