Question

4/3+5/2-7/3=
(3/5)(6/7)(-4)=
2/3 / 5/8=
ayuda

Answer 1

PARA EL PRIMER PROBLEMA =

$x = ( \frac{4}{3} + \frac{5}{2}) - \frac{7}{3} \\ x = (( \frac{2}{2} )(\frac{4}{3} ) + ( \frac{3}{3}) ( \frac{5}{2} ) )- ( \frac{2}{2} )(\frac{7}{3} ) \\ x = (\frac{ 8}{6} + \frac{15}{6} ) - \frac{14}{6} \\ x = \frac{9}{6} + ( \frac{14}{6} - \frac{14}{6} ) \\ x = \frac{9}{6} \\ x = \frac{3}{2}$

PARA EL SEGUNDO PROBLEMA =

$y = ( \frac{3}{5} )( \frac{6}{7} )( - 4) \\ y =( \frac{3}{5} \times \frac{6}{7} )( - 4) \\ y = ( \frac{18}{35} )( - 4) \\ y = - ( \frac{18 \times 4}{35 \times 1} ) \\ y = \frac{72}{35}$

PARA EL TERCER PROBLEMA =

$z = (\frac{ \frac{2}{3} }{ \frac{5}{8} } ) \\ z = (\frac{2 \times 8}{5 \times 3} ) \\ z = \frac{16}{15}$

Saludossssssss!!!!!!!!........