Question

(4×+3)(4×+4)=
(6×+7)(6×+3)=
(10+7)(10+7)=
(3×+2)(3×+9)=
(9×+6)(9×+3)=

Answer 1

Respuesta:

(4×+3)(4×+4)= 16$x^{2}$+16x+12x+12

16$x^{2}$+28x+12

(6×+7)(6×+3)= 36$x^{2}$+18x+42x+21

36$x^{2}$+60x+21

(10x+7)(10x+7)= Aquí aplicamos las leyes de los exponentes, se suman los exponentes al ser bases iguales, obteniendo $(10x+7)^{2}$

(3×+2)(3×+9)= 9$x^{2}$+27x+6x+11

9$x^{2}$+33x+18

(9×+6)(9×+3)= 81$x^{2}$+27x+54x+18

81$x^{2}$+81x+18