Question

4-2(d + 7)-(3d + 5)=2d+(4d-9+3d)-(d - 3) ayudaaa, con procedimiento

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Answer 1

Respuesta:

4-2(d + 7)-(3d + 5)=2d+(4d-9+3d)-(d - 3)

4-2d-14-3d-5=2d+(7d-9)-d+3

-15-5d=2d+7d-9-d+3

-15-5d=8d-6

-5d-8d=-6+15

-13d=9

d=$-\frac{9}{13}$